November 2018 1 232 Report
Berdasarkan data :
a. Fe2+ + 2e → Fe E° = -0,44volt
b. Pb2+ + 2e → Pb E°= -0,14volt
c. Zn2+ + 2e → Zn. E° = -0,76volt

Jelaskan kesepontanan reaksi dibawah ini :
a. Fe2+ + Zn → Fe + Zn2+
b. Zn2+ + Pb → Zn + Pb2+
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