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Jumlah mol NH4Cl = 0,2 x 100 = 20 mmol
[OH^-] = 1 x 10^-5 x 40/20
= 2 x 10^-5
pOH = - log 2 x 10^-5
= 5 - log 2
= 5 - 0,3
= 4,7
pH = 14 - 4,7 = 9,3