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jumlah mol NaOH = 25 x 0,1 = 2,5 mmol
CH3COOH (aq) + NaOH (aq) --> CH3COONa (aq) + H2O (l)
Awal 5 mmol 2,5 mmol - -
Bereaksi -2,5 mmol -2,5 mmol +2,5 mmol -
Akhir 2,5 mmol - 2,5 mmol
[H^+] = 1 x10^-5 x 2,5/2,5
= 1 x 10^-5
pH = -log 1 x 10^-5
= 5 - log 1
= 5