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Verified answer
Rumus :y - y1/y2 - y1 = x - x1/x2 - x1
a]
C [-1,4]
D[1,3]
x1 = -1
y1 = 4
x2 = 1
y2 = 3
y - 4/3 - 4 = x - [-1]/ 3 - [-1]
y-4 / -1 = x+2 / 4
4[y-4] = x+2
4y-16 = x+2
4y-x-18 = 0.
Jadi, persamaan garis yg melalui titik C[-1,4] dan D[1,3] adl 4y-x-18 = 0.
b]
F[0,4]
G[-3,5]
x1 = 0
x2 = -3
y1 = 4
y2 = 5
y-4 / 5-4 = x-0 / -3-0
y-4 = x-0 / -3
-3[y-4] = x-0
-3y + 12 = x-0
-3y-x+12 = 0.
Jadi, persamaan garis yg melalui titik F[0,4] dan G[-3,5] adl -3y-x+12 = 0.
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