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Verified answer
Persamaan Garis Lurus:g//h
M1 = M2
M1 = 3
[2,3]
x1 = 2
y1 = 3
y = mx + c
Rumus:
y - y1 = m[x - x1]
y - 3 = 3[x - 2]
y - 3 = 3x - 2
⇒ y - 3x - 1 = 0.
Jadi, persamaan garis yang melewati titik [2,3] dan sejajar dengan garis yg persamaannya y = 3x + 1 adalah y - 3x - 1 = 0.
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