Question

Tentukan persamaan garis yang melalui titik k ( -1,0) L (3,-8)

Answer 1

Y₁ = 0
y₂ = -8
x₁ = -1
x₂ = 3
y - y₁ = x - x₁
y₂ - y₁    x₂ - x₁
y - 0   = x - ( -1 )
-8 - 0      3 - ( -1 )
y - 0 = x + 1
  -8          4
4 ( y - 0 ) = -8 ( x + 1 )
4y - 0      = -8x - 8
8x + 4y + 8  = 0

Answer 2

Y-y1/y2-y1 = x-x1/x2-x1
y-0/-8-0 = x+1/3+1
y-0/-8 = x+1/4
4(y-0) = -8(x+1)
4y-0 = -8x-8
8x+4y+8-0 = 0
8x+4y+8=0 atau 4y= -8x-8