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2y+x=6
2y=-x+6
y=-½x+6
m=-½
syarat sejajar m1=m2
persamaan garis melalui titik (-3,2) dan m=-½
y-y1=m(x-x1)
y-2=-½(x-(-3))
y-2=-½(x+3)
-2(y-2)=x+3
-2y+4=x+3
2y+x+3-4=0
2y+x-1=0