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a = 4 dan b = -3
gradien (m) tegak lurus = b/a = - 3/4
maka,
pers. grs. melalui ttk.(2,-7) dan m = - 3/4 :
y-y1 = m(x-x1)
y-(-7) = - 3/4 (x-2)
y+7 = - 3/4 (x-2)
kedua ruas dikalikan dg 4, menjadi :
4(y+7) = -3(x-2)
4y+28 = -3x+6
3x+4y+28-6 = 0
3x+4y+22 = 0 atau 3x+4y = -22