Jawaban:
2 + √3
Penjelasan dengan langkah-langkah:
tan 285°
= tan (360° - 75°)
= tan 75°
= tan (30° + 45°)
= (tan 30° + tan 45°)/(1 - tan 30° . tan 45°)
= (1/√3 + 1)/(1 - 1/√3 . 1)
= ((1 + √3)/√3) / ((√3 - 1)/√3)
= (√3 + 1)/(√3 - 1) . (√3 + 1)/(√3 + 1)
= (3 + 2√3 + 1)/(3 - 1)
= (4 + 2 √3)/2
= 2 + √3
Kode Kategorisasi : 10.2.6
Kelas 10
Pelajaran Matematika
Bab 6 - Trigonometri Dasar
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Jawaban:
2 + √3
Penjelasan dengan langkah-langkah:
tan 285°
= tan (360° - 75°)
= tan 75°
= tan (30° + 45°)
= (tan 30° + tan 45°)/(1 - tan 30° . tan 45°)
= (1/√3 + 1)/(1 - 1/√3 . 1)
= ((1 + √3)/√3) / ((√3 - 1)/√3)
= (√3 + 1)/(√3 - 1) . (√3 + 1)/(√3 + 1)
= (3 + 2√3 + 1)/(3 - 1)
= (4 + 2 √3)/2
= 2 + √3
Kode Kategorisasi : 10.2.6
Kelas 10
Pelajaran Matematika
Bab 6 - Trigonometri Dasar