Question

Tentukan persamaan garis singgung pada kurva!

Answer 1

A)
y = 1 - 2x- 3x²
f(x) = 1 - 2x - 3x²

f'(x) = -2 -6x
f'(-2) = -2 - 6(-2)
f'(-2) = -2 + 12
f'(-2) = 10
m = 10

di titik (-2, -7)

persamaan garis
y - y1 = m(x - x1)
y - (-7) = 10(x - (-2))
y + 7 = 10(x + 2)
y + 7 = 10x + 20
y = 10x + 20 - 7
y = 10x + 13

b.
y = 1 / x²
f(x) = 1 / x²

f'(x) = -2/x³
f'(1) = -2/(1)³
f'(1) = -2
m = -2

di titik (1, 1)

persamaan garis
y - y1 = m(x - x1)
y - 1 = -2(x - 1)
y - 1 = -2x + 2
y = -2x + 2 + 1
y = -2x + 3