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2y = 3x - 6
y = - 3
=
Syarat tegak lurus : x = -1
x = -1
= -1 :
= -1 x
=
Persamaan garis melalui titik (-5, -4) dengan =
(y - ) = (x - )
y - (-4) = (x - (-5))
3(y + 4) = -2(x + 5)
3y + 12 = -2x - 10
3y + 2x + 12 + 10 = 0
3y + 2x + 22 = 0
Jadi persamaan garis yang melalui titik (-5, -4) dan tegak lurus dengan garis 3x - 2y - 6 = 0 adalah 3y + 2x + 22 = 0
#Jadikan jawaban paling cerdas ya,...(capek ngetik dan jawabnya),....hehehe....
-2y=-3x+6
y=-3/-2 x+6/-2
y=3/2 x-3,m1=3/2
m1 . m2=-1
3/2 . m2 =-1
m2=-1 : 3/2
m2=-1 . 2/3
m2=-2/3
x1=-5 y1=-4
y-y1=m2(x-x1)
y+4=-2/3(x+5)
y+4=-2/3 x-10/3
y=-2/3 x-10/3-4
y=-2/3 x-22/3,atau
(y=-2/3x-22/3) dikali 3
3y=-2x-22