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y-y1 = m(x-x1)
y-4 = 2(x-3)
y-4 = 2x-6
y = 2x-6+4
y = 2x-2
jawaban soal nomer 2
y-y1 = m(x-x1)
y-5 = 4(x+3)
y-5 = 4x+12
y = 4x+12+5
y = 4x+17
Nomor satu
(y - 4) = 2(x - 3)
y - 4 = 2x - 6
y = 2x - 6 + 4
y = 2x - 2
Nomor dua
(y - 5) = 4(x - (-3) )
y - 5 = 4(x + 3)
y - 5 = 4x + 12
y = 4x + 12 + 5
y = 4x + 17