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Koordinat kutub (r , α)
r = √{(-5√3)² + 5²}
= √(75 + 25)
= √100
= 10
Tan a = 5/-5√3
Tan a = 1/-√3
Tan a = -1/3 √3
a = 150°
koordinat kutubnya (10 , 150°)
39.
r = √(x² + y²)
r = √(√3)² + (1)²)
r = √(3 + 1)
r = √4
r = 2
tan a = y/x
tan a = √3/1
tan a = √3
a = 60°
koordinat kutubnya (2 , 60°)
yg lain silakan coba sndiri ya caranya sama koq