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Verified answer
Persamaan Kuadratmemotong sb x di (-2,0) dan (3,0)
y = a(x - (-2))(x - 3)
y = a(x + 2)(x - 3)
memotong sb y di (0,3)
y = a(x + 2)(x - 3)
3 = a(0 + 2)(0 - 3)
3 = a(2 × (-3))
3 = -6a
a = -3/6
a = -1/2
Persamaan kuadrat :
y = a(x + 2)(x - 3)
y = -1/2 (x² - x - 6)
y = -1/2 x² + 1/2 x + 3
▶
f(x) = -1/2 x² + 1/2 x + 3