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3x+4y=1
⇒4x+4y=-4
3x+4y=1
→x=-5
2x+2y=-2
2(-5)+2y=-2
-10+2y=-2
2y=8
y=4
~D
7x-1=0 ---2
1. substitusi 2.eliminasi
7x=1 x=1/7 (1)×7 & (2)×2
2y=-16/7 14x+14y+14=0 (1)'
y=-8/7 14x-2=0 (2)'
(1)' - (2)'
14y+16=0
14y=-16 y=-8/7
14x-16+14=0
14x=2 x=1/7
jadi, (x,y)=( 1/7 , - 8/7 )