Question

Tentukan nilai potong kurva y = x^2 - 5 dan garis y = 2x + 3

Answer 1

Verified answer

Y = x² - 5
y = 2x + 3

y = y
x² - 5 = 2x + 3
x² - 2x - 5 - 3 = 0
x² - 2x - 8 = 0
(x + 2) (x - 4) = 0
x = -2     x = 4

tipot = (-2, -1)   dan   (4,11)
(x = -2)
→ y = 2(-2) + 3
→ y = -1

(x = 4)
→ y = 2(4) + 3
→ y = 11