Question

Tentukan nilai p dan q
H(x)=px+q.sedangkan h(-6)=32 dan h(4)=-8

Answer 1

H(x) = px + q
h(-6) = -6p + q =32
                     q = 32 + 6p.........pers 1
h(4) = 4p + q = -8............pers 2
maka :
4p + q = -8
4p + 32 + 6p = -8
10p + 32 = -8
10p         = -8 -32
p             = -40/10 = -4
p = -4 jd 4p + q = -8
              4x-4 + q = -8
               -16 + q = -8
                        q = -8 + 16 = 8
sehingga p = -4 dan q = 8