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a = 1
b = 3
c = k
Syarat akar kembar:
D = 0
b^2 - 4ac = 0
3^2 - 4 . 1 . k = 0
9 - 4k = 0
9 = 4k
k = 9/4 = 2 1/4
2. kx^2 + (3k - 1)x + k - 3 = 0
a = k
b = 3k - 1
c = k - 3
Syarat akar kembar:
D = 0
b^2 - 4ac = 0
(3k - 1)^2 - 4 . k . (k - 3) = 0
9k^2 - 6k + 1 - 4k^2 + 12k = 0
5k^2 + 6k + 1 = 0
5k^2 + 5k + k + 1 = 0
5k(k + 1) + 1(k + 1) = 0
(k + 1)(5k + 1) = 0
k = -1 atau k = -1/5