Question

Titik balik fungsi f(x) = 2(x + 2)² + 3 adalah

a. (-2, -3)
b. (-2, 3)
c. (3, -2)
d. (2, -3)
e. (2, 3)

Answer 1

F(x) = 2(x + 2)² + 3
f(x) = 2(x² + 4x + 4) + 3
f(x) = 2x² + 8x + 8 + 3
f(x) = 2x² + 8x + 11
a = 2      b = 8    c = 11

rumus titik balik
x = -b/2a
x = -8/2(2)
x = -8/4
x = -2

f(x) = 2x² + 8x + 11
f(-2) = 2(-2)² + 8(-2) + 11
        = 2(4) - 16 + 11
         = 8 - 5
         = 3

Titik balik = (-2,3)

Answer 2

Titik balik fungsi yaitu (-2,3)
Perhitungan Terlampir