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Verified answer
IntegralMisal
u = 5 - x³
du/dx = -3x²
3x² dx = - du
6x³ dx = - 2 du
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∫6x² √(5 - x³) dx
= ∫u ^1/2 . -2 du
= -2/(3/2) . u ^3/2 + C
= -4/3 (5 - x³)√(5 - x³) + C
Verified answer