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t=7 cm
T=15
s²=T²+r²=15²+8²=225+64=289
s=√289=17 cm
Luas permukaan
=L tabung tanpa tutup + L selimut kerucut
=πr(r+2t) + πrs
=πr(r+2t+s)
=3,14 . 8 (8+2.7+17)
=25,12(8+14+17)
=25,12(39)
=979,68 cm²