" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2x-2y+z =8 ..pers II
3x+2y+z = 2 .. pers III
eliminasi salah satu variable dulu.
pers I... x + y + 2z = 0 I x1 ..> x + y + 2z = 0
pers II... 2x-2y+z = 8 I x2 --> 4x-4y+2z = 16
------------------------- -
-3x + 5y = -16 .. pers I-II
pers II.. 2x-2y+z = 8
pers III.. 3x+2y+z = 2
--------------------- -
-x - 4y = 6 .. pers II-III
pers I-II .. -3x +5y = -16 I x1 --> -3x + 5y = -16
pers II-III - x -4y = 6 I x3 --> -3x -12y = 18
------------------------ -
17y = -34
y = -2
subtitusikan y = -2 ke pers II-III utk mencari nilai x,
-x - 4y = 6
-x - 4(-2) = 6
-x + 8 = 6
-x = -2
x = 2
subtitusikan x=2 dan y= -2 ke pers I
x+y+2z = 0
2+(-2) + 2z = 0
2z = 0
z = 0
shg x= 2, y= -2 , z =0