a. PET = 3
N= golongan5 nonlogam > 2,5
H= golongan 1 nonlogam > 1
cari PEB = (golongan pusat - pet x elektron valensi nonpusat) : 2
= (5 - 3 x 1) : 2
= (5-3) : 2
=2:2
PEB=1 maka karna ada peb, ikatan kovalen polar
b. PET= 4
C=golongan 4 nonlogam
H= golongan 1 nonlogam
PEB = (4 - 4 x 1) ;2
=(4-4 ):2
=0:2
PEB=0 maka karna tidak ada peb, ikatan kovalen nonpolar
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a. PET = 3
N= golongan5 nonlogam > 2,5
H= golongan 1 nonlogam > 1
cari PEB = (golongan pusat - pet x elektron valensi nonpusat) : 2
= (5 - 3 x 1) : 2
= (5-3) : 2
=2:2
PEB=1 maka karna ada peb, ikatan kovalen polar
b. PET= 4
C=golongan 4 nonlogam
H= golongan 1 nonlogam
PEB = (4 - 4 x 1) ;2
=(4-4 ):2
=0:2
PEB=0 maka karna tidak ada peb, ikatan kovalen nonpolar