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(2x-1) (x+3) ≤ 0
2x-1 = 0
2x = 1
x = 1/2
atau
x+3 = 0
x = -3
garis bilangan
uji x = 0 maka hasilnya bil -
+++++ - - - - - ++++++
-3 1/2
tanda ≤ maka penyelesaian yg -
Hp = { x | -3 ≤ x ≤ 1/2 }