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a = 56
b = 51-56 = -5
Sn = -36
Sn = n/2 (2a+(n-1)b)
-36 = n/2 (2.56+(n-1)-5)
-36 = n/2 (112-5n+5)
-36 = n/2 (117-5n) --> kdua ruas dikali 2
-72 = n (117-5n)
-72 = 117n-5n²
5n²-117n-72 = 0
(5n+3)(n-24) = 0
n = -3/5 (tdk mgkin)
n = 24
jd banyak suku ada 24