Question

Tentukan akar persamaan berikut.
a. 3x-12
b. x pangkat 2+7x+6.
c. -3x pangkat 2-5x+2

mohon dijawab yah. terima kasih

Answer 1

A. 3x-12
x = -12-3
x = -15
b, x²+7x+6 = 0
a = 1
b = 7 ; (p+q) = 7
c = 6 ; (p.q) = 6
p = 1
q = 6

x²+7x+6 = 0
(x+1) (x+6) = 0

x + 1 = 0, x + 6 = 0
x1 = -1. x2 = -6
HP{-1,-6}

c. -3x²+x-5x+2 = -3x2+x-4x+2 = 0
= (-3x²+x) + (4x+2) = 0
= x ( -3x+1) + 2 (-3x+1) = 0
= (-3x+1) (x+2) = 0

-3-1 = 0. x+2 = 0
-3x = 1. atau x2 = -2
x1 = -⅓
HP{-⅓,-2}