1. Massa NaOH= 10% X 100
= 10 gram
Massa H2O( air) = 100 - 10 =90 gram
Mr NaOH= 40 dan Mr air= 18 jadi
nt= gram / mr
=40/20= 1/2
np= 90/18= 5
Xp= np/np+ nt
= 5/5+1/2=5/11/2= 10/11
Xt= nt/nt+np= 1/2/1/2+5= 1/11
2. nt= 10/60= 1/6
np= 27/18=3/2
Xp=np/np+nt= 3/2/3/2+1/6= 3/2/5/3= 9/10
P= p° X xp
= 30 mmHg x 9/10= 27 mmHg
3. ∆Tb= m.kb
100.208-100= 72/mr x 1/1 x 0.52
0.208= 37.44/mr
Mr= 180
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1. Massa NaOH= 10% X 100
= 10 gram
Massa H2O( air) = 100 - 10 =90 gram
Mr NaOH= 40 dan Mr air= 18 jadi
nt= gram / mr
=40/20= 1/2
np= 90/18= 5
Xp= np/np+ nt
= 5/5+1/2=5/11/2= 10/11
Xt= nt/nt+np= 1/2/1/2+5= 1/11
2. nt= 10/60= 1/6
np= 27/18=3/2
Xp=np/np+nt= 3/2/3/2+1/6= 3/2/5/3= 9/10
P= p° X xp
= 30 mmHg x 9/10= 27 mmHg
3. ∆Tb= m.kb
100.208-100= 72/mr x 1/1 x 0.52
0.208= 37.44/mr
Mr= 180