Question

Lim x-->2 [(x-2).cos(πx-2π)/tan(2πx-4π)] = ....

Answer 1

Jawab:

limit trigonometri

bentuk  0/0 --> lim (x - >0)   (ax )/ tan (bx)  = a/b

Penjelasan dengan langkah-langkah:

limit (x -> 2)  [ (x - 2) . cos ( πx - 2π) ] / [ tan (2πx - 4π) ] =

.

= lim (x -> 2) [ (x - 2) . cos π(x - 2) ] / [ tan 2π (x - 2)]

= lim(x->2) cos  π(x - 1) .  limit (x- >2)  [ (x- 2 )/ tan  2π (x - 2) ]

=  1  .  1/(2π)

= 1/(2π)