Tam, gdzie się da trzeba zastosować wzór skróconego mnożenia. Z góry dzięki ;)
a)(x-1)²-(x-1)(x+1)=
b) (x+3)²-(x-3)²-1²=
c)(x-4y)²-(4y+x)²=
d)(2x+3y)(2x-3y)-(2x-3y)²=
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a)
b)
c)
d)
a)(x-1)²-(x-1)(x+1)=x^2-2x+1-(x^2-1)=x^2-2x+1-x^2+1=-2x+2
b) (x+3)²-(x-3)²-1²=x^2+6x+9-(x^2-6x+9)-1=x^2+6x+9-x^2+6x-9-1=12x-1
c)(x-4y)²-(4y+x)²=x^2-8xy+16y^2-(16y^2+8xy+x^2)=x^2-8xy+16y^2-16y^2-8xy-x^2=
=-16xy
d)(2x+3y)(2x-3y)-(2x-3y)²=4x^2-9y^2-(4x^2-12xy+9y^2)=4x^2-9y^2-4x^2+12xy-9y^2=
=-18y^2+12xy