Odpowiedź:
7.
2^16 * 5^8/[2^5 * (5²)³] : 2³/5^6 = 2^11 * 5^8/5^6 : 2³ * 5^6 = 2^8 * 5² * 5^6 =
= 268 8 568 = 1068
8.
h =1/2 ah
a = 5,4 * 10^5m
h = 6,3 * 10^8m
P = 1/2 * 5,4 * 10^5 * 6,3 * 10^8m² = 34,02 * 10^13m = 3,402 * 10^14m²
Pole tego trojkata wynosi 3,402 * 10^14m².
Szczegółowe wyjaśnienie:
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Odpowiedź:
7.
2^16 * 5^8/[2^5 * (5²)³] : 2³/5^6 = 2^11 * 5^8/5^6 : 2³ * 5^6 = 2^8 * 5² * 5^6 =
= 268 8 568 = 1068
8.
h =1/2 ah
a = 5,4 * 10^5m
h = 6,3 * 10^8m
P = 1/2 * 5,4 * 10^5 * 6,3 * 10^8m² = 34,02 * 10^13m = 3,402 * 10^14m²
Pole tego trojkata wynosi 3,402 * 10^14m².
Szczegółowe wyjaśnienie: