a) (∛7)³+(∛27)³=7+27=34
b) (∛4)³+∛125 :(-5)=4+5:(-5)=4+(-1)=4-1=3
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a) (∛7)³+(∛27)³=7+27=34
b) (∛4)³+∛125 :(-5)=4+5:(-5)=4+(-1)=4-1=3