Question

Szkola letnia !

rozlóż na iloczyn: 2a^2+2b^2+12c^2-5ab-11ac+10bc

Answer 1

2a²-a(5b+11c)+(2b²+12c²+10bc)=2a²-a(5b+11c)+2(b²+5bc+6c²)=
wspolczynnik przy b²  1=1*1, przy c²   6=2*3
2a²-a(5b+11c)+2(b+2c)(b+3c)
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(b+3c)-2*2(b+2c)=b+3c-4b-8c=-5b-11c=-(5b+11c)
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2=1*2  i -2(b+2c)*[-(b+3c)]
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[a-2(b+2c)]*[2a-(b+3c)]=
(a-2b-4c)*(2a-b-3c)