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2⁻³*∛8²=(½)³*∛(2³)²=(½)³*2²=½
odp. A
zad.2.
x - procent ceny podstawowej po obniżce
x*270=216
x=0,8=80%
100%-80%=20% - procent obniżki
odp. B
zad.3.
y-x-1=0
x+y-3=0
y=x+1
x+x+1-3=0
2x=2
x=1
y=2
odp. A
zad.4.
f(-1)=2*(-1)³-(-1)² + 2*(-1)-5=-2-1-2-5=-10
odp. C
216---------x
x=216*100% / 270= 80%
100%-80%=20%