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x1 + x2 = -b/a = -2/3
x1.x2 = c/a = -1/3
akar-akar yang baru: α = 1/x1 dan β = 1/x2
Rumus persamaan baru: x² - (α + β)x + α.β = 0
Hitung; α+β = 1/x1 + 1/x2 =(x2 + x1)/x1.x2
= (-2/3)/(-1/3)
= 2
αβ = 1/x1.1/x2 = 1/x1.x2
= 1/(-1/3)
= -3
jadi persamaannya adalah x² -2x - 3 = 0