a = 3i1/3
b = 3i1/3+2i1/24
a+b+c = 9
10/3+10/3+19/24+c = 9
20/3+9/24+c = 9
160/24+9/24+c = 9
169/24+c = 9
c = 9-169/24
c = 216/24-169/24
c = 47/24
c = 1 i 23/24
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a = 3i1/3
b = 3i1/3+2i1/24
a+b+c = 9
10/3+10/3+19/24+c = 9
20/3+9/24+c = 9
160/24+9/24+c = 9
169/24+c = 9
c = 9-169/24
c = 216/24-169/24
c = 47/24
c = 1 i 23/24
a= 3¹/₃
b= 3¹/₃ + 2 ¹/₂₄= ¹⁰/₃ + ⁴⁹/₂₄ = ⁸⁰/₂₄ + ⁴⁹/₂₄ = ¹²⁹/₂₄ (tutaj pisze w liczniku 129 wyjaśniam bo słabo widać) = 5 ³/₈
c= 9 - 5 ³/₈ = 3 ⁵/₈ - tyle wynosi trzecia liczba
10/3 + 10/3 + 49/24 + x = 9
20/3 + 49/24 + x = 9
160/24 + 49/24 + x = 9
209/24 + x = 9
x = 216/24 - 209/24
x = 7/24
Odp. Trzecia liczba to 7/24