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πr²+πR²=45π
P1=4P2
4πR²+πR²=45π
5R²=45
R²=9
R=3
πR²=9π- pole pierwszego kola
stad 45π-9π=36π= pole drugiego kola
πr²=36π
r²=36
r=6
2πr= 12π
2πR=6π
Obwody pozostaja w stosunku: 6/12 czyli 1:2