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2x +1 - druga liczba
2x+3 - trzecia liczba
(2x-1)² + (2x+1)² + (2x+3)² = 251
4x² - 4x + 1 + 4x² + 4x + 1 + 4x² + 12x + 9 = 251
12x² +12x - 240 = 0
x² + x - 20 = 0
Δ = 81
√Δ = 9
liczby mialy byc dodatnie wiec x = 4
szukane liczby to: 7, 9, 11.