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U10=a+(10-1)b=50>>>a+9b=50
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-5b=-20
b=4
Jika b=4
U5=a+4.4=30
a+16=30
a=14
Pertanyaannya adalah S7=7/2(28+32)
S7=7/2.60
S7=210
U5 = a + (5-1)b = 30
U10 = a + (10-1)b = 50
menggunakan metode eliminasi
a + (5-1)b = 30
a + (10-1)b = 50
a + 4b = 30
a + 9b = 50
-5b = 20
b = 20/5
b = 4
a + (5-1)b = 30
a + 4(4) = 30
a + 16 = 30
a = 30 - 16
a = 14
U7 = a + (n-1)b
U7 = 14 + (7-1)4
U7 = 14 + 6.4
U7 = 14 + 24
U7 = 38
Bila dicari jumlah ketujuh suku pertama dari barisan tersebut
Sn = n/2 ( 2a+(n-1)b)
S7 = 7/2 (2.14+(7-1)4
S7 = 7/2 (28+6.4)
S7 = 7/2 (28+24)
S7 = 7/2 . 52
S7 = 182