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horner
|1 -2 a b
-1|v -1 3 -a-3
________________ +
1 -3 a+3 b-a-3
f(x) = (x+1) (x²-3x+a+3)+ (b-a-3)
horner 2
| 1 -3 a+3
3 | v 3 0
________________+
1 0 a+3
f(x) = (x+1) [(x-3) (x) + (a+3)] + (b-a-3)
f(x) = (x+1) (x-3) (x) + (x+1) (a+3) +(b-a-3)
s(x) = ax+3x+a+3+b-a-3
x-4 = ax +3x+b
x-3x-4 = ax+b
-2x-4 =ax+b
a= -2 b=-4