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p(-2) = 41
Dan,
x² - x - 2 = (x+1)(x-2)
Sehingga,
p(-1) = 8(-1)+25
p(-1) = -8 + 25
p(-1) = 17
p(2) = 8(2)+25
p(2) = 16+25
p(2) = 41
Sehingga untuk sisa pembagian oleh x²-4 = (x+2)(x-2) memiliki sisa mx + n
Sehingga,
p(-2) = -2m + n = 41
p(2) = 2m + n = 41
Dengan menguranginya:
-4m = 0
m = 0
Dan didapat pula:
2m+n = 41
2(0) + n = 41
n = 41
Sehingga, sisanya adalah:
S(x) = 0x + 41
S(x) = 41