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(2x-3) (x+1)
f(x+1)= ax+b f(2x-3)=ax+b
f(-1)=10 f(3/2)=5
-a+b=10........1) 3/2a+b=5 ..............2)
dieliminasikan persamaan 1 & 2
-a+b=10( dikalikan 2)
3/2a+b=5 ( dikalikan 2)
-2a+2b=20 -2a+2b=20
3a+2b=10 - -2 x -2 +2b=20
-5a=10 4+2b=20
a= -2 2b=20-4
2b= 18
b=9
maka sisanya ax+b⇒ -2x+9