Question

Suku banyak 6x3 - 17x2 + cx - 6 habis dibagi oleh (2x-3). nilai c = a. -16 b. 8 c. 24 d. -8 e. 16

Answer 1

2x-3= 0
x= 3/
f(3/2)= 6(3/2)^3 - 17(3/2)^2 + c(3/2) - 6 = 0
= 162/8 - 153/4 + 3c/2 - 6 =0
= 162/8 - 306/8 + 12c/8 - 48/8 = 0
= -192/8 + 12c/8 = 0
= -192 +12c =0
192 = 12c
c= 16