Question

Suatu fungsi linier didefinisikan oleh f(x)=ax+b. Jika f(2) = 8 dan f(4)= 12, maka nilai dari 3a – b adalah....
A) -1
B) 2
C) 24
D) 10

Answer 1

Verified answer

F(x) = ax + b
f(2) = 8
f(4) = 12

maka
f(2) = 2a + b = 8
f(4) = 4a + b = 12

sisa
-2a = -4
a = -4/-2
a = 2

2a + b = 8
2(2) + b = 8
4 + b = 8
b = 8- 4
b = 4

nilai dari
3a - b
= 3(2) - 4
= 6 - 4
= 2