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Verified answer
Kelas 8 qf(x) = ax + b
f(-2) = -2a + b = 14
f(3) = 3a + b = -1
3a + b = -1
-2a + b = 14
-------------------- -
5a = -15
a = -3
-2a + b = 14
-2 . 3 + b = 14
b = 14 + 6
b = 20
f(x) = -3x + 20
f(7) = -3 . 7 + 20
f(7) = -21 + 20
f(7) = -1
Verified answer
F(x) = ax+bf(-2) = -2a+b = 14
f(3) = 3a+b = -1
gunakan metode eliminasi :
3a + b = -1
-2a + b = 14
——————— -
5a = -15
a = -3
kemudian, metode substitusi :
⇔-2a + b = 14
⇔-2(-3) + b = 14
⇔6 + b = 14
⇔b = 14 - 6
⇔b = 8
nilai f(7) :
f(x) = ax+b
⇔f(7) = -3(7) + 8
⇔f(7) = -21 + 8
⇔f(7) = -13