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Verified answer
Mapel : MatematikaBab : Lingkaran
____________
Keliling Juring
= (120/360) x Keliling lingkaran
= (1/3) x 2 x 22/7 x 42
= (1/3) x 44 x 6
= 44 x 2
= 88 cm
Maka panjang kawat minimal
= 88 x 4
= 352 m → Opsi B