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f(x) = ax + b ⇒ f(3) = 3a + b = -1
↓
-5a = 15
a = -3
⇒ 3a + b = -1
-9 + b = -1
b = 8
⇒ f(5) = 5a + b
= 5(-3) + 8
= -15 + 8
= -7
f(3) = 3a + b = -1
f(-2) dan f(3) dikurangi diperoleh
-5a = 15
a = -3, masukkan dlm f(-2) atau f(3)
f(3) = 3(-3) + b = -1
-9 + b = -1
b = -1 +9 = 8
f(x) = -3x + 8
f(5) = -3(5) + 8 = -15 +8 = -7