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f(3) = 15
a.3+b = 15
3a+b = 15 ... (i)
f(5) = 20
a.5+b = 20
5a+b = 20 ... (ii)
eliminasi (i)&(ii)
3a+b = 15
5a+b = 20
___________ -
-2a = -5
a = 5/2
disubstitusikan ke (i) :
3a+b = 15
3.5/2 + b = 15
15/2 + b = 15
b = 15 - 15/2
b = 30/2 - 15/2
b = 15/2
a) nilai a = 5/2 dan b = 15/2
b) bentuk fungsi : f(x) = 5/2 x + 15/2
c)
f(-2)
= 5/2 . (-2) + 15/2
= 5.(-1) + 15/2
= -5 + 15/2
= -10/2 + 15/2
= -5/2 atau -2 1/2