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ar = 8
" suku ke 5
ar^4 = 64
ar . r³ = 64
8 r³ = 64
r³ = 8
r = 2
ar = 8
a.2 = 8
a = 4
jumlah sepuluh suku pertama
S10 = a(r^n - 1)/(r-1)
= 4(2^10 - 1)./(2-1)
= 4(1024 - 1)/1
= 4092
jumlah n suku pertama deret geometriSn = a(r^n - 1)/(r-1)
= 4(2^n - 1)(2 - 1)
= 2^2 .(2^n - 1)
= 2^2 . 2^n - 2^2
= 2^(n+2) - 4