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3g + 2g = 5g
3g magnezu ----- 5g tlenku magnezu
9g magnezu ----- xg tlenku magnezu
x = 15g tlenku magnezu
2 mole Mg - 2 mole MgO
48g Mg - 80g MgO
9 g Mg - xg MgO
x= 15g MgO
lub (to rozwiązanie bardziej wynika z treści zadania):
mMg/mO = 3/2 , mMg= 9g
9g/mO = 3/2
3mO = 2*9
mO= 6g
mMgO = mO + mMg = 9g+ 6g = 15g