Stosując metodę wyłączania spólnego czynnika rozóż wielomian W na czynniki b) W(x)=x^2(x-1)-x+1
W(x)=x^2(x-1)-x+1
Liczę na naj :)
W(x) = x^2(x-1) -x+1
W(x) = x^2(x-1) -(x-1)
W(x) = (x^2-1)(x-1)
W(x) = (x-1)(x+1)(x-1)
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W(x)=x^2(x-1)-x+1
Liczę na naj :)
W(x) = x^2(x-1) -x+1
W(x) = x^2(x-1) -(x-1)
W(x) = (x^2-1)(x-1)
W(x) = (x-1)(x+1)(x-1)